2.2: Simplifying Algebraic Expressions (2024)

  1. Last updated
  2. Save as PDF
  • Page ID
    18334
    • 2.2: Simplifying Algebraic Expressions (1)
    • Anonymous
    • LibreTexts

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\)

    \( \newcommand{\vectorC}[1]{\textbf{#1}}\)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}}\)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}}\)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)

    \(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)

    Learning Objectives
    • Apply the distributive property to simplify an algebraic expression.
    • Identify and combine like terms.

    Distributive Property

    The properties of real numbers are important in our study of algebra because a variable is simply a letter that represents a real number. In particular, the distributive property states that given any real numbers \(a, b,\) and \(c\),

    \[\color{Cerulean}{a}\color{black}{(b+c)=}\color{Cerulean}{a}\color{black}{b+}\color{Cerulean}{a}\color{black}{c}\]

    This property is applied when simplifying algebraic expressions. To demonstrate how it is used, we simplify \(2(5−3)\) in two ways, and observe the same correct result.

    Certainly, if the contents of the parentheses can be simplified, do that first. On the other hand, when the contents of parentheses cannot be simplified, multiply every term within the parentheses by the factor outside of the parentheses using the distributive property. Applying the distributive property allows you to multiply and remove the parentheses.

    Example \(\PageIndex{1}\)

    Simplify:

    \(5(7y+2)\).

    Solution:

    Multiply \(5\) times each term inside the parentheses.

    \(\begin{aligned}\color{Cerulean}{5}\color{black}{(7y+2)}&=\color{Cerulean}{5}\color{black}{\cdot 7y+}\color{Cerulean}{5}\color{black}{\cdot 2} \\ &=35y+10 \end{aligned}\)

    Answer:

    \(35y+10\)

    Example \(\PageIndex{2}\)

    Simplify:

    \(−3(2x^{2}+5x+1)\).

    Solution:

    Multiply \(−3\) times each of the coefficients of the terms inside the parentheses.

    Answer:

    \(-6x^{2}-15x-3\)

    Example \(\PageIndex{3}\)

    Simplify:

    \(5(−2a+5b)−2c\).

    Solution:

    Apply the distributive property by multiplying only the terms grouped within the parentheses by \(5\).

    2.2: Simplifying Algebraic Expressions (2)

    Figure \(\PageIndex{1}\)

    Answer:

    \(-10a+25b-2c\)

    Because multiplication is commutative, we can also write the distributive property in the following manner:

    \[(b+c)a=ba+ca\]

    Example \(\PageIndex{4}\)

    Simplify:

    \((3x−4y+1)⋅3\).

    Solution:

    Multiply each term within the parentheses by \(3\).

    \(\begin{aligned} (3x-4y+1)\cdot 3&=3x\color{Cerulean}{\cdot 3}\color{black}{-4y}\color{Cerulean}{\cdot 3}\color{black}{+1}\color{Cerulean}{\cdot 3} \\ &=9x-12y+3 \end{aligned}\)

    Answer:

    \(9x-12y+3\)

    Division in algebra is often indicated using the fraction bar rather than with the symbol (\(÷\)). And sometimes it is useful to rewrite expressions involving division as products:

    \(\begin{array}{c}{\color{black}{\frac{x}{\color{Cerulean}{5}}=\frac{1x}{5}=\color{Cerulean}{\frac{1}{5}}\color{black}{\cdot x}}} \\{\color{black}{\frac{\color{Cerulean}{3}\color{black}{ab}}{\color{Cerulean}{7}}=\frac{3}{7}\cdot \frac{ab}{1}=\color{Cerulean}{\frac{3}{7}}\color{black}{\cdot ab}}}\\{\frac{x+y}{\color{Cerulean}{3}}=\frac{1}{3}\cdot \frac{(x+y)}{1}=\color{Cerulean}{\frac{1}{3}}\color{black}{\cdot (x+y)}} \end{array}\)

    Rewriting algebraic expressions as products allows us to apply the distributive property.

    Example \(\PageIndex{5}\)

    Divide:

    \(\frac{25x^{2}-5x+10}{5}.

    Solution:

    First, treat this as \(\frac{1}{5}\) times the expression in the numerator and then distribute.

    \(\begin{aligned} \frac{25x^{2}-5x+10}{\color{Cerulean}{5}}&=\frac{1}{5}\cdot\frac{(25x^{2}-5x+10)}{1} \\ &=\color{Cerulean}{\frac{1}{5}}\color{black}{\cdot (25x^{2}-5x+10)} &\color{Cerulean}{Multiply\:each\:term\:by\:\frac{1}{5}.} \\ &=\color{Cerulean}{\frac{1}{5}}\color{black}{\cdot 25x^{2}-}\color{Cerulean}{\frac{1}{5}}\color{black}{\cdot 5x+}\color{Cerulean}{\frac{1}{5}}\color{black}{\cdot 10}&\color{Cerulean}{Simplify.} \\ &=5x^{2}-x+2 \end{aligned}\)

    Alternate Solution:

    Think of \(5\) as a common denominator and divide each of the terms in the numerator by \(5\):

    \(\begin{aligned} \frac{25x^{2}-5x+10}{5}&=\frac{25x^{2}}{5}-\frac{5x}{5}+\frac{10}{5} \\ &=5x^{2}-x+2 \end{aligned}\)

    Answer:

    \(5x^{2}-x+2\)

    We will discuss the division of algebraic expressions in more detail as we progress through the course.

    Exercise \(\PageIndex{1}\)

    Simplify:

    \(\frac{1}{3}(−9x+27y−3)\).

    Answer

    \(-3x+9y-1\)

    Combining Like Terms

    Terms with the same variable parts are called like terms, or similar terms. Furthermore, constant terms are considered to be like terms. If an algebraic expression contains like terms, apply the distributive property as follows:

    \(\begin{array}{c}{2\color{Cerulean}{a}\color{black}{+3}\color{Cerulean}{a}\color{black}{=(2+3)}\color{Cerulean}{a}\color{black}{=5}\color{Cerulean}{a}}\\{7\color{Cerulean}{xy}\color{black}{-5}\color{Cerulean}{xy}\color{black}{=(7-5)}\color{Cerulean}{xy}\color{black}{=2}\color{Cerulean}{xy}}\\{10\color{Cerulean}{x^{2}}\color{black}{+4}\color{Cerulean}{x^{2}}\color{black}{-6}\color{Cerulean}{x^{2}}\color{black}{=(10+4-6)}\color{Cerulean}{x^{2}}\color{black}{=8}\color{Cerulean}{x^{2}}} \end{array}\)

    In other words, if the variable parts of terms are exactly the same, then we may add or subtract the coefficients to obtain the coefficient of a single term with the same variable part. This process is called combining like terms. For example,

    \(3a^{2}b+2a^{2}b=5a^{2}b\)

    Notice that the variable factors and their exponents do not change. Combining like terms in this manner, so that the expression contains no other similar terms, is called simplifying the expression. Use this idea to simplify algebraic expressions with multiple like terms.

    Example \(\PageIndex{6}\)

    Simplify:

    \(3a+2b−4a+9b\).

    Solution:

    Identify the like terms and combine them.

    \(\begin{aligned} 3a+2b-4a+9b&=3\color{Cerulean}{a}\color{black}{-4}\color{Cerulean}{a}\color{black}{+2}\color{OliveGreen}{b}\color{black}{+9}\color{OliveGreen}{b}&\color{Cerulean}{Commutative\:property\:of\:addition} \\ &=-1a+11b &\color{Cerulean}{Combine\:like\:terms.} \\ &=-a+11b \end{aligned}\)

    Answer:

    \(-a+11b\)

    In the previous example, rearranging the terms is typically performed mentally and is not shown in the presentation of the solution.

    Example \(\PageIndex{7}\)

    Simplify:

    \(x^{2}+3x+2+4x^{2}−5x−7\).

    Solution:

    Identify the like terms and add the corresponding coefficients.

    \(\begin{array}{lc}{\color{Cerulean}{\underline{1x^{2}}}\color{black}{+}\color{OliveGreen}{\underline{\underline{3x}}}\color{black}{+\underline{\underline{\underline{2}}}+}\color{Cerulean}{\underline{4x^{2}}}\color{black}{-}\color{OliveGreen}{\underline{\underline{5x}}}\color{black}{-\underline{\underline{\underline{7}}}}}&{\color{Cerulean}{Identify\:like\:terms.}}\\{=5x^{2}-2x-5}&{\color{Cerulean}{Combine\:like\:terms.}}\end{array}\)

    Answer:

    \(5x^{2}-2x-5\)

    Example \(\PageIndex{8}\)

    Simplify:

    \(5x^{2}y−3xy^{2}+4x^{2}y−2xy^{2}\).

    Solution:

    Remember to leave the variable factors and their exponents unchanged in the resulting combined term.

    \(\begin{array}{l}{\underline{5x^{2}y}-\underline{\underline{3xy^{2}}}+\underline{4x^{2}y}-\underline{\underline{2xy^{2}}}}\\{=9x^{2}y-5xy^{2}} \end{array}\)

    Answer:

    \(9x^{2}y-5xy^{2}\)

    Example \(\PageIndex{9}\)

    Simplify:

    \(\frac{1}{2}a−\frac{1}{3}b+\frac{3}{4}a+b\).

    To add the fractional coefficients, use equivalent coefficients with common denominators for each like term.

    \(\begin{aligned} \frac{1}{2}a-\frac{1}{3}b+\frac{3}{4}a+1b&=\frac{1}{2}a+\frac{3}{4}a-\frac{1}{3}b+1b \\ &=\frac{2}{4}a+\frac{3}{4}a-\frac{1}{3}b+\frac{3}{3}b \\&=\frac{5}{4}a+\frac{2}{3}b \end{aligned}\)

    Answer:

    \(\frac{5}{4}a+\frac{2}{3}b\)

    Example \(\PageIndex{10}\)

    Simplify:

    \(−12x(x+y)^{3}+26x(x+y)^{3}\).

    Solution:

    Consider the variable part to be \(x(x+y)^{3}\). Then this expression has two like terms with coefficients \(−12\) and \(26\).

    \(\begin{aligned} &-12x(x+y)^{3}+26x(x+y)^{3} &\color{Cerulean}{Add\:the\:coefficients.} \\ &=14x(x+y)^{3} \end{aligned}\)

    Answer:

    \(14x(x+y)^{3}\)

    Exercise \(\PageIndex{2}\)

    Simplify:

    \(−7x+8y−2x−3y\).

    Answer

    \(−9x+5y\)

    Distributive Property and Like Terms

    When simplifying, we will often have to combine like terms after we apply the distributive property. This step is consistent with the order of operations: multiplication before addition.

    Example \(\PageIndex{11}\)

    Simplify:

    \(2(3a−b)\)−\(7(−2a+3b)\).

    Solution:

    Distribute \(2\) and \(−7\) and then combine like terms.

    2.2: Simplifying Algebraic Expressions (3)

    Figure \(\PageIndex{2}\)

    Answer:

    \(20a-23b\)

    In the example above, it is important to point out that you can remove the parentheses and collect like terms because you multiply the second quantity by \(−7\), not just by \(7\). To correctly apply the distributive property, think of this as adding \(−7\) times the given quantity, \(2(3a−b)+(−7)(−2a+3b)\).

    Exercise \(\PageIndex{3}\)

    Simplify:

    \(−5(2x−3)+7x\).

    Answer

    \(-3x+15\)

    Often we will encounter algebraic expressions like \(+(a+b)\) or \(−(a+b)\). As we have seen, the coefficients are actually implied to be \(+1\) and \(−1\), respectively, and therefore, the distributive property applies using \(+1\) or \(–1\) as the factor. Multiply each term within the parentheses by these factors:

    \[+(a+b)=+1(a+b)=(+1)a+(+1)b=a+b\]

    \[-(a+b)=-1(a+b)=(-1)a+(-1)b=-a-b\]

    This leads to two useful properties,

    \[+(a+b)=a+b\]

    \[-(a+b)=-a-b\]

    Example \(\PageIndex{12}\)

    Simplify:

    \(5x−(−2x^{2}+3x−1)\).

    Solution:

    Multiply each term within the parentheses by \(−1\) and then combine like terms.

    2.2: Simplifying Algebraic Expressions (4)

    Figure \(\PageIndex{3}\)

    Answer:

    \(2x^{2}+2x+1\)

    When distributing a negative number, all of the signs within the parentheses will change. Note that \(5x\) in the example above is a separate term; hence the distributive property does not apply to it.

    Example \(\PageIndex{13}\)

    Simplify:

    \(5−2(x^{2}−4x−3)\).

    Solution:

    The order of operations requires that we multiply before subtracting. Therefore, distribute \(−2\) and then combine the constant terms. Subtracting \(5 − 2\) first leads to an incorrect result, as illustrated below:

    \(\begin{array}{c|c}{\underline{\color{red}{Incorrect!}}}&{\underline{\color{Cerulean}{Correct!}}}\\{\begin{aligned} &\color{red}{5-2}\color{black}{(x^{2}-4x-3)} \\ &=\color{red}{3}\color{black}{(x^{2}-4x-3)}\\&=3x^{2}-12x-9\quad\color{red}{x} \end{aligned}}&{\begin{aligned}&5\color{Cerulean}{-2}\color{black}{(x^{2}-4x-3)} \\ &=5\color{Cerulean}{-2}\color{black}{x^{2}}\color{Cerulean}{+8}\color{black}{x}\color{Cerulean}{+6} \\ &=-2x^{2}+8x+11\quad\color{Cerulean}{\checkmark} \end{aligned}} \end{array}\)

    Answer:

    \(-2x^{2}+8x+11\)

    Note

    It is worth repeating that you must follow the order of operations: multiply and divide before adding and subtracting!

    Exercise \(\PageIndex{4}\)

    Simplify:

    \(8−3(−x^{2}+2x−7)\).

    Answer

    \(3x^{2}-6x+29\)

    Example \(\PageIndex{14}\)

    Subtract \(3x−2\) from twice the quantity \(−4x^{2}+2x−8\).

    Solution:

    First, group each expression and treat each as a quantity:

    \((3x-2)\qquad\text{and}\qquad (-4x^{2}+2x-8)\)

    Next, identify the key words and translate them into a mathematical expression.

    2.2: Simplifying Algebraic Expressions (5)

    Figure \(\PageIndex{4}\)

    Finally, simplify the resulting expression.

    Answer:

    \(-8x^{2}+x-14\)

    Key Takeaways

    • The properties of real numbers apply to algebraic expressions, because variables are simply representations of unknown real numbers.
    • Combine like terms, or terms with the same variable part, to simplify expressions.
    • Use the distributive property when multiplying grouped algebraic expressions, \(a(b+c)=ab+ac\).
    • It is a best practice to apply the distributive property only when the expression within the grouping is completely simplified.
    • After applying the distributive property, eliminate the parentheses and then combine any like terms.
    • Always use the order of operations when simplifying.
    Exercise \(\PageIndex{5}\) Distributive Property

    Multiply.

    1. \(3(3x−2)\)
    2. \(12(−5y+1)\)
    3. \(−2(x+1)\)
    4. \(5(a−b)\)
    5. \(\frac{5}{8}(8x−16)\)
    6. \(−\frac{3}{5}(10x−5)\)
    7. \((2x+3)⋅2\)
    8. \((5x−1)⋅5\)
    9. \((−x+7)(−3)\)
    10. \((−8x+1)(−2)\)
    11. \(−(2a−3b)\)
    12. \(−(x−1)\)
    13. \(\frac{1}{3}(2x+5)\)
    14. \(−\frac{3}{4}(y−2)\)
    15. \(−3(2a+5b−c)\)
    16. \(−(2y^{2}−5y+7)\)
    17. \(5(y^{2}−6y−9)\)
    18. \(−6(5x^{2}+2x−1)\)
    19. \(7x^{2}−(3x−11)\)
    20. \(−(2a−3b)+c\)
    21. \(3(7x^{2}−2x)−3\)
    22. \(\frac{1}{2}(4a^{2}−6a+4)\)
    23. \(−\frac{1}{3}(9y^{2}−3y+27)\)
    24. \((5x^{2}−7x+9)(−5)\)
    25. \(6(\frac{1}{3}x^{2}−\frac{1}{6}x+\frac{1}{2})\)
    26. \(−2(3x^{3}−2x^{2}+x−3)\)
    27. \(\frac{20x+30y−10z}{10}\)
    28. \(\frac{−4a+20b−8c}{4}\)
    29. \(\frac{3x^{2}−9x+81}{−3}\)
    30. \(\frac{15y^{2}+20y−5}{5}\)
    Answer

    1. \(9x−6 \)

    3. \(−2x−2 \)

    5. \(5x−10 \)

    7. \(4x+6 \)

    9. \(3x−21 \)

    11. \(−2a+3b\)

    13. \(\frac{2}{3}x+\frac{5}{3}\)

    15. \(−6a−15b+3c\)

    17. \(5y^{2}−30y−45\)

    19. \(7x^{2}−3x+11\)

    21. \(21x^{2}−6x−3\)

    23. \(−3y^{2}+y−9\)

    25. \(2x^{2}−x+3\)

    27. \(2x+3y−z\)

    29. \(−x^{2}+3x−27\)

    Exercise \(\PageIndex{6}\) Distributive Property

    Translate the following sentences into algebraic expressions and then simplify.

    1. Simplify two times the expression \(25x^{2}−9\).
    2. Simplify the opposite of the expression \(6x^{2}+5x−1\).
    3. Simplify the product of \(5\) and \(x^{2}−8\).
    4. Simplify the product of \(−3\) and \(−2x^{2}+x−8\).
    Answer

    1. \(50x^{2}−18\)

    3. \(5x^{2}−40\)

    Exercise \(\PageIndex{7}\) Combining Like Terms

    Simplify.

    1. \(2x−3x\)
    2. \(−2a+5a−12a\)
    3. \(10y−30−15y\)
    4. \(\frac{1}{3}x+\frac{5}{12}x\)
    5. \(−\frac{1}{4}x+\frac{4}{5}+\frac{3}{8}x\)
    6. \(2x−4x+7x−x\)
    7. \(−3y−2y+10y−4y\)
    8. \(5x−7x+8y+2y\)
    9. \(−8α+2β−5α−6β\)
    10. \(−6α+7β−2α+β\)
    11. \(3x+5−2y+7−5x+3y\)
    12. \(–y+8x−3+14x+1−y\)
    13. \(4xy−6+2xy+8\)
    14. \(−12ab−3+4ab−20\)
    15. \(\frac{1}{3}x−\frac{2}{5}y+\frac{2}{3}x−\frac{3}{5}y\)
    16. \(\frac{3}{8}a−\frac{2}{7}b−\frac{1}{4}a+\frac{3}{14}b\)
    17. \(−4x^{2}−3xy+7+4x^{2}−5xy−3\)
    18. \(x^{2}+y^{2}−2xy−x^{2}+5xy−y^{2}\)
    19. \(x^{2}−y^{2}+2x^{2}−3y\)
    20. \(\frac{1}{2}x^{2}−\frac{2}{3}y^{2}−\frac{1}{8}x^{2}+\frac{1}{5}y^{2}\)
    21. \(\frac{3}{16}a^{2}−\frac{4}{5}+\frac{1}{4}a^{2}−\frac{1}{4}\)
    22. \(\frac{1}{5}y^{2}−\frac{3}{4}+\frac{7}{10}y^{2}−\frac{1}{2}\)
    23. \(6x^{2}y−3xy^{2}+2x^{2}y−5xy^{2}\)
    24. \(12x^{2}y^{2}+3xy−13x^{2}y^{2}+10xy\)
    25. \(−ab^{2}+a^{2}b−2ab^{2}+5a^{2}b\)
    26. \(m^{2}n^{2}−mn+mn−3m^{2}n+4m^{2}n^{2}\)
    27. \(2(x+y)^{2}+3(x+y)^{2}\)
    28. \(\frac{1}{5}(x+2)^{3}−\frac{2}{3}(x+2)^{3}\)
    29. \(−3x(x^{2}−1)+5x(x^{2}−1)\)
    30. \(5(x−3)−8(x−3)\)
    31. \(−14(2x+7)+6(2x+7)\)
    32. \(4xy(x+2)^{2}−9xy(x+2)^{2}+xy(x+2)^{2}\)
    Answer

    1. \(−x\)

    3. \(−5y−30\)

    5. \(\frac{1}{8}x+\frac{4}{5}\)

    7. \(y\)

    9. \(−13α−4β\)

    11. \(−2x+y+12\)

    13. \(6xy+2\)

    15. \(x−y\)

    17. \(−8xy+4\)

    19. \(3x^{2}−y^{2}−3y\)

    21. \(\frac{7}{16}a^{2}−\frac{21}{20}\)

    23. \(8x^{2}y−8xy^{2}\)

    25. \(6a^{2}b−3ab^{2}\)

    27. \(5(x+y)^{2}\)

    29. \(2x(x^{2}−1)\)

    31. \(−8(2x+7)\)

    Exercise \(\PageIndex{8}\) Mixed Practice

    Simplify.

    1. \(5(2x−3)+7\)
    2. \(−2(4y+2)−3y\)
    3. \(5x−2(4x−5)\)
    4. \(3−(2x+7)\)
    5. \(2x−(3x−4y−1)\)
    6. \((10y−8)−(40x+20y−7)\)
    7. \(\frac{1}{2}y−\frac{3}{4}x−(\frac{2}{3}y−\frac{1}{5}x)\)
    8. \(\frac{1}{5}a−\frac{3}{4}b+\frac{3}{15}a−\frac{1}{2}b\)
    9. \(\frac{2}{3}(x−y)+x−2y\)
    10. \(−\frac{1}{3}(6x−1)+\frac{1}{2}(4y−1)−(−2x+2y−\frac{1}{6})\)
    11. \((2x^{2}−7x+1)+(x^{2}+7x−5)\)
    12. \(6(−2x^{2}+3x−1)+10x^{2}−5x\)
    13. \(−(x^{2}−3x+8)+x^{2}−12\)
    14. \(2(3a−4b)+4(−2a+3b)\)
    15. \(−7(10x−7y)−6(8x+4y)\)
    16. \(10(6x−9)−(80x−35)\)
    17. \(10−5(x^{2}−3x−1)\)
    18. \(4+6(y^{2}−9)\)
    19. \(\frac{3}{4}x−(\frac{1}{2}x^{2}+\frac{2}{3}x−\frac{7}{5})\)
    20. \(−\frac{7}{3}x^{2}+(−\frac{1}{6}x^{2}+7x−1)\)
    21. \((2y^{2}−3y+1)−(5y^{2}+10y−7)\)
    22. \((−10a^{2}−b^{2}+c)+(12a^{2}+b^{2}−4c)\)
    23. \(−4(2x^{2}+3x−2)+5(x^{2}−4x−1)\)
    24. \(2(3x^{2}−7x+1)−3(x^{2}+5x−1)\)
    25. \(x^{2}y+3xy^{2}−(2x^{2}y−xy^{2})\)
    26. \(3(x^{2}y^{2}−12xy)−(7x^{2}y^{2}−20xy+18)\)
    27. \(3−5(ab−3)+2(ba−4)\)
    28. \(−9−2(xy+7)−(yx−1)\)
    29. \(−5(4α−2β+1)+10(α−3β+2)\)
    30. \(\frac{1}{2}(100α^{2}−50αβ+2β^{2})−\frac{1}{5}(50α^{2}+10αβ−5β^{2})\)
    Answer

    1. \(10x−8\)

    3. \(−3x+10\)

    5. \(−x+4y+1\)

    7. \(−\frac{11}{20}x−\frac{1}{6}y\)

    9. \(\frac{5}{3}x−\frac{8}{3}y\)

    11. \(3x^{2}−4\)

    13. \(3x−20\)

    15. \(−118x+25y\)

    17. \(−5x^{2}+15x+15\)

    19. \(−\frac{1}{2}x^{2}+\frac{1}{12}x+\frac{7}{5}\)

    21. \(−3y^{2}−13y+8\)

    23. \(−3x^{2}−32x+3\)

    25. \(−x^{2}y+4xy^{2}\)

    27. \(−3ab+10\)

    29. \(−10α−20β+15\)

    Exercise \(\PageIndex{9}\) Mixed Practice

    Translate the following sentences into algebraic expressions and then simplify.

    1. What is the difference of \(3x−4\) and \(−2x+5\)?
    2. Subtract \(2x−3\) from \(5x+7\).
    3. Subtract \(4x+3\) from twice the quantity \(x−2\).
    4. Subtract three times the quantity \(−x+8\) from \(10x−9\).
    Answer

    1. \(5x-9\)

    3. \(-2x-7\)

    Exercise \(\PageIndex{10}\) Discussion Board Topics
    1. Do we need a distributive property for division, \((a+b)÷c\)? Explain.
    2. Do we need a separate distributive property for three terms, \(a(b+c+d)\)? Explain.
    3. Explain how to subtract one expression from another. Give some examples and demonstrate the importance of the order in which subtraction is performed.
    4. Given the algebraic expression \(8−5(3x+4)\), explain why subtracting \(8−5\) is not the first step.
    5. Can you apply the distributive property to the expression \(5(abc)\)? Explain why or why not and give some examples.
    6. How can you check to see if you have simplified an expression correctly? Give some examples.
    Answer

    1. Answers may vary

    3. Answers may vary

    5. Answers may vary

    2.2: Simplifying Algebraic Expressions (2024)
    Top Articles
    Instant Pot 101: 50 Keto Instant Pot Recipes for Weight Loss
    60 Homemade Christmas Candy Recipes to Sweeten Your Holiday Season
    Pollen Count Centreville Va
    Amc Near My Location
    Www.craigslist Virginia
    Craglist Oc
    2024 Fantasy Baseball: Week 10 trade values chart and rest-of-season rankings for H2H and Rotisserie leagues
    Melfme
    7.2: Introduction to the Endocrine System
    Unlocking the Enigmatic Tonicamille: A Journey from Small Town to Social Media Stardom
    Tanger Outlets Sevierville Directory Map
    Minn Kota Paws
    2021 Tesla Model 3 Standard Range Pl electric for sale - Portland, OR - craigslist
    Celsius Energy Drink Wo Kaufen
    Walgreens On Nacogdoches And O'connor
    Citymd West 146Th Urgent Care - Nyc Photos
    RBT Exam: What to Expect
    This Modern World Daily Kos
    Mills and Main Street Tour
    Nashville Predators Wiki
    Lazarillo De Tormes Summary and Study Guide | SuperSummary
    Virginia New Year's Millionaire Raffle 2022
    Recap: Noah Syndergaard earns his first L.A. win as Dodgers sweep Cardinals
    Nurse Logic 2.0 Testing And Remediation Advanced Test
    Rugged Gentleman Barber Shop Martinsburg Wv
    Christina Steele And Nathaniel Hadley Novel
    Tips on How to Make Dutch Friends & Cultural Norms
    Weve Got You Surrounded Meme
    Stockton (California) – Travel guide at Wikivoyage
    Evil Dead Rise Ending Explained
    My Reading Manga Gay
    Kristy Ann Spillane
    Franklin Villafuerte Osorio
    Dentist That Accept Horizon Nj Health
    Why Are The French So Google Feud Answers
    The Latest: Trump addresses apparent assassination attempt on X
    Que Si Que Si Que No Que No Lyrics
    Kstate Qualtrics
    Today's Final Jeopardy Clue
    Louisville Volleyball Team Leaks
    Dynavax Technologies Corp (DVAX)
    Frcp 47
    Cdcs Rochester
    Housing Intranet Unt
    Me Tv Quizzes
    Suffix With Pent Crossword Clue
    Craigslist Freeport Illinois
    Hazel Moore Boobpedia
    Craigslist Rooms For Rent In San Fernando Valley
    Poster & 1600 Autocollants créatifs | Activité facile et ludique | Poppik Stickers
    Jigidi Jigsaw Puzzles Free
    Zom 100 Mbti
    Latest Posts
    Article information

    Author: Neely Ledner

    Last Updated:

    Views: 5803

    Rating: 4.1 / 5 (62 voted)

    Reviews: 93% of readers found this page helpful

    Author information

    Name: Neely Ledner

    Birthday: 1998-06-09

    Address: 443 Barrows Terrace, New Jodyberg, CO 57462-5329

    Phone: +2433516856029

    Job: Central Legal Facilitator

    Hobby: Backpacking, Jogging, Magic, Driving, Macrame, Embroidery, Foraging

    Introduction: My name is Neely Ledner, I am a bright, determined, beautiful, adventurous, adventurous, spotless, calm person who loves writing and wants to share my knowledge and understanding with you.